Fabricate a 90 Degree Elbow from pipe

Fabricate a 90 Degree Elbow from pipe

         Fabricate a 90 Degree Elbow From Pipe

Formula

D= Dia of pipe(given)

R= 1.5D/1D/5D As per req

CF=2­Πr

Length of pipe required= Cf/360×Deg of Elbow

Deg cut=Deg/no of pieces (Given)

L1∞L2=(Tan deg of cut)×OD

Cutting mark=(L1∞L2)/2 From divided point

Example

Fabricate a 1.5D and 90 degree elbow 10”OD Sch 40 and make it with 4 no of pieces.

Required Length of pipe to fabricate

OD=10”      =10.75Inch (from pipe sch table)

                    =10.750×25.4=273mm

R=1.5D       =273×1.5=410mm

cF                =2×3.14×410=2576mm

Length of pipe req=cf/360×Deg of elbow

Deg of elbow=90

Length of pipe req =2576/360×90=644mm

Adding cutting and grinding allowances of 15mm its is 659 mm

Deg of cut= Deg/ no of pieces=90/4=22.5

L1∞L2=(Tan Deg cut)×OD=0.414×273=113mm

Cutting mark=(L1∞L2)/2from divided point =56